Graphing a line in quadrant 1

Introduction

We graph a line whose equation is given, say for example y = 3x. We need at least two points or ordered pairs to graph the line. First we choose some x values. Then we evaluate y = 3x for each value of x.

For example for x = 0, y = 30 = 0; x = 1, y = 31 = 3 and so on. We put the x, y and the ordered pair x,y values as follows.

x	y	x,y
0	30 = 0	0,0
1	31 = 3	1,3
2	32 = 6	2,6
3	33 = 9	3,9
4	34 = 12	4,12

We see that the ordered pairs lie in the quadrant 1. Joining the points will give the graph of the line in quadrant 1.

Example 1

Graph the line in the quadrant 1, whose equation is given below.

2x y = 3

Solution

Step 1:

Given equation 2x y = 3; for y = 0, x = 3/2; for x = 2, y = 223 = 43 = 1. So two ordered pairs are 3/2,0 2,1

Step 2:

Plotting the points and joining with a line we get

Example 2

Graph the line in the quadrant 1, whose equation is given below.

x + 3y = 1

Solution

Step 1:

Given equation x + 3y = 1; for y = 0, x = 1; For x = 0, y = 1/3. So two ordered pairs are 1,0 and 0,1/3

Step 2:

Plotting the points and joining with a line we get

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